Someone messaged me with a question and I'm not sure why my answer is different. Does anyone know?

I need your help to solve this equation.

How much heat is required to raise the temperature of 100lbs of water from 10F to 120F?

Answer: 24,300 btuh

It looks like we first have to melt 100 pounds of ice into water. It takes 144 BTU's to melt 1 pound of ice into 32F water. So 100 pounds of ice x 144 BTU's = 14,400 BTU's.

Now we take 120F - 32F = 88F. This is how many degrees we need to heat the water from 32F to get to 120F.

88F x 100 pounds = 8800 BTU's.

8800 BTU's + 14,400 BTU's = 23,200 BTU's.

It's close to the answer you have. I'm not sure why my answer is different though.